integration tutorial: analysis

Consider the integral
int [ (e2y - e-2y) / ey ] dy
This is an indefinite integral, so we need to find the most general antiderivative of the integrand f(y).
To find an antiderivative of f(y), we go through our list of integration methods:
  1. Recognize elementary antiderivatives
  2. Rewrite the integrand to make it easier
  3. Use substitution to reverse the chain rule or simplify the integrand
  4. Use integration by parts
  5. Use inspection to see the value of a definite integral
to find one that works for this integrand. In this case, only one method is appropriate. We can rewrite the integrand: break the integrand into two terms and use rules of exponents to combine the resulting ratios of exponentials to give an expression that is more easily integrable. This is shown below.
Rewriting:
Break the integrand into two terms and use rules of exponents to combine the resulting ratios of exponentials to rewrite the integral:
[ (e2y - e-2y) / ey ] = ey - e-3y.
This can be broken into separate integrals,
int [ (e2y - e-2y) / ey ] dy =inteydy+int-e-3ydy
which can be evaluated using basic antidifferentiation, and substitution (of "ax"), respectively, to obtain
inteydy+int-e-3ydy = (ey) + ((1/3) e-3y) + C.

Explanation for rewritten term(s)
Basic antidifferentiation
In this case, by using rules for basic antiderivatives we can just write down the antiderivative of the integrand:
int ey dy = ey + C

Substitution (of "ax")
Let w = -3 y. Then w' = -3, so (1/(-3)) dw = dy. The integral can therefore be rewritten as

int -e-3y dy = int -ew (1/(-3)) dw = (1/3) ew + C
Thus, substituting back for w,
int -e-3y dy = (1/3) e-3y + C

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integration analysis
Last Modified: Wed Feb 6 13:53:59 EST 2002
Comments to glarose@umich.edu
©2002 Gavin LaRose, UM Math Dept.