integration tutorial: analysis
Consider the integral

[
er / sqrt(
er) ]
dr
This is an indefinite integral,
so we need to find
the most general
antiderivative of the integrand f(r).
To find an antiderivative of
f(
r), we go through
our list of integration methods:
- Recognize elementary antiderivatives
- Rewrite the integrand to make it easier
- Use substitution to reverse the chain rule or simplify the
integrand
- Use integration by parts
- Use inspection to see the value of a definite
integral
to find one that works for this integrand. In this case,
there are several methods that work. We can use substitution
to rewrite the integrand in terms of
w =
er, or can rewrite the integrand: use properties of the exponents to combine numerator and
denominator of the fraction to give an expression that is more easily integrable.
This is shown below:
substitution;
rewriting.
Substitution:
Let
w =
er. Then
w' =
er, so
dw =
er dr.
The integral can therefore be rewritten as

[
er / sqrt(
er) ]
dr =

1/sqrt(
w)
dw =
2 sqrt(
w) +
C
Thus, substituting back for
w,

[
er / sqrt(
er) ]
dr =
2 sqrt(
er) +
C
Rewriting:
Use properties of the exponents to combine numerator and
denominator of the fraction to rewrite the integral:
[ er / sqrt(er) ]
=
er/2.
Thus,

[
er / sqrt(
er) ]
dr
=
er/2dr
which can be evaluated using
substitution (of "ax"), to obtain
er/2dr
=
(2
er/2) +
C.
Explanation for rewritten term(s)
Substitution (of "ax")Let
w = 1/2
r. Then
w' = 1/2, so
(1/(1/2))
dw =
dr.
The integral can therefore be rewritten as
er/2 dr =
ew (1/(1/2))
dw =
2
ew +
C
Thus, substituting back for
w,
er/2 dr =
2
er/2 +
C
Note that when there are multiple integration
methods the antiderivatives may appear to be different but are
actually the same function shifted vertically by different constants.
This is reasonable because the most general antiderivative is only
unique up to an additive constant.
integration analysis
Last Modified: Wed Feb 6 13:53:59 EST 2002
Comments to
glarose@umich.edu
©2002 Gavin LaRose, UM Math Dept.