integration tutorial: analysis
Consider the integral
-p/2p/2 x cos(
x)
dx
This is a definite integral,
so we need to find
the area under the integrand f(x),
which we do by using the Fundamental Theorem of Calculus: we find an
antiderivative, evaluate it at the endpoints of the integral, and
take the difference of the values.
To find an antiderivative of
f(
x), we go through
our list of integration methods:
- Recognize elementary antiderivatives
- Rewrite the integrand to make it easier
- Use substitution to reverse the chain rule or simplify the
integrand
- Use integration by parts
- Use inspection to see the value of a definite
integral
to find one that works for this integrand. In this case,
there are several methods that work. We can use integration by parts
to rewrite the product of
u =
x and
v' = cos(
x) in the integrand using the integration by parts formula, or use inspection to determine the value of the integral.
This is shown below:
integration by parts;
inspection.
Integration by parts:
Let
u =
x and
v' = cos(
x).
Then
u' = 1 and
v = sin(
x),
so, remembering the integration by parts formula
u v'
dx =
u v -
u'
v dx,
we have
x cos(
x)
dx
=
(
x) (sin(
x)) -

(1) (sin(
x))
dx
=
x sin(
x) + cos(
x) +
C.
To evaluate the definite integral, we take this antiderivative,
evaluate it at the endpoints of the integral (-pi/2 and pi/2),
and take the difference of the values. This gives
[ (pi/2) sin((pi/2)) + cos((pi/2)) ] - [ (-pi/2) sin((-pi/2)) + cos((-pi/2)) ] = 0.
Inspection:
Note that
we are integrating on odd function over an
interval symmetric about the y-axis. Because the function is odd, the
area to the left of the axis will be the negative of the area to the
right, and the value of the integral must be 0.
integration analysis
Last Modified: Wed Feb 6 13:53:59 EST 2002
Comments to
glarose@umich.edu
©2002 Gavin LaRose, UM Math Dept.