To find an antiderivative of
f(
t), we go through
our list of integration methods:
- Recognize elementary antiderivatives
- Rewrite the integrand to make it easier
- Use substitution to reverse the chain rule or simplify the
integrand
- Use integration by parts
- Use inspection to see the value of a definite
integral
to find one that works for this integrand. In this case,
only one method is appropriate. We use substitution to rewrite the integrand in terms of
w = ln(3
t).
This is shown below.
Substitution:
Let
w = ln(3
t). Then
w' = 1/
t, so
dw = (1/
t)
dt.
The integral can therefore be rewritten as

ln(3
t)/
t dt =
w dw =
(1/2)
w2 +
C
Thus, substituting back for
w,

ln(3
t)/
t dt =
(1/2) ln(3
t)
2 +
C
To evaluate the definite integral, we take this antiderivative,
evaluate it at the endpoints of the integral (1/3 and 5),
and take the difference of the values. This gives
[ (1/2) ln(3(5))2 ] - [ (1/2) ln(3(1/3))2 ] = (1/2) ln(15)2.