To find an antiderivative of
f(
s), we go through
our list of integration methods:
- Recognize elementary antiderivatives
- Rewrite the integrand to make it easier
- Use substitution to reverse the chain rule or simplify the
integrand
- Use integration by parts
- Use inspection to see the value of a definite
integral
to find one that works for this integrand. In this case,
only one method is appropriate. We use substitution to rewrite the integrand in terms of
w = ln(
s3).
This is shown below.
Substitution:
Let
w = ln(
s3). Then
w' = 3/
s, so
dw = (3/
s)
ds.
The integral can therefore be rewritten as

[ 3 / (
s ln(
s3) ) ]
ds =

1/
w dw =
ln(
w) +
C
Thus, substituting back for
w,

[ 3 / (
s ln(
s3) ) ]
ds =
ln(ln(
s3)) +
C
To evaluate the definite integral, we take this antiderivative,
evaluate it at the endpoints of the integral (2 and e),
and take the difference of the values. This gives
[ ln(ln((e)3)) ] - [ ln(ln((2)3)) ] = ln(3) - ln(ln(8)).