Derivatives of Sums
Example:
G = (2 + ln(2)) z8 + 2*z - 5
The first thing to notice when finding the derivative of this function
is that it is
the sum of several terms,
as shown in color below:
| G |
= |
( (2 + ln(2)) z8 ) | + |
( 2*z ) |
- |
( 5 ) |
The Derivative Rule for Sums:
The derivative of a sum is the sum of the derivatives.
If
then the derivative of
z is
| |
z' |
= |
( f(x) |
+ |
g(x) )' |
| |
|
= |
f '(x) |
+ |
g'(x) |
So our example,
| G |
= |
( (2 + ln(2)) z8 ) | + |
( 2*z ) |
- |
( 5 ) |
we can think of as
So the derivative is
| G ' |
= ( |
f(z) |
+ |
g(z) |
- |
h(z) |
)' |
| |
= |
f '(z) |
+ |
g '(z) |
- |
h '(z) |
|
| |
= |
( (2 + ln(2)) z8) ' |
+ |
( 2*z) ' |
- |
( 5) ' |
|
and we just need to know each of the derivatives on the right-hand
side of the equation. In this case these are
so the finished derivative is
| G ' |
= |
(0 + 0) z8 + 8*(2 + ln(2)) z7 |
+ |
2 |
- |
0 |
|
| |
= |
8*z7 (2 + ln(2)) + 2 |
additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
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Page Generated: Sun Mar 1 15:55:05 2026
Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose,
University of Michigan Math Dept.