Derivatives of Sums

Example:
y = cos(q) + (sin(q))2

The first thing to notice when finding the derivative of this function is that it is the sum of several terms, as shown in color below:

y = ( cos(q) ) + ( (sin(q))2 )

The Derivative Rule for Sums:

The derivative of a sum is the sum of the derivatives.
If
  z = ( f(x) + g(x) )
then the derivative of z is
  z' = ( f(x) + g(x) )'
    = f '(x) + g'(x)

So our example,

y = ( cos(q) ) + ( (sin(q))2 )
we can think of as
y = f(q) + g(q)
So the derivative is
y ' = ( f(q) + g(q) )'
  = f '(q) + g '(q)  
  = ( cos(q)) ' + ( (sin(q))2) '  
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( cos(q) )' = (-1)*sin(q) (by the derivative rules for basic functions)
( (sin(q))2 )' = 2*sin(q) cos(q) (by the chain rule)
so the finished derivative is
y ' = (-1)*sin(q) + 2*sin(q) cos(q)  
  = (-1)*sin(q) + 2*sin(q) cos(q)
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additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.