Derivatives of Sums

Example:
z = ((p)*p)5 - 2*p2 - p

The first thing to notice when finding the derivative of this function is that it is the sum of several terms, as shown in color below:

z = ( ((p)*p)5 ) - ( 2*p2 ) - ( p )

The Derivative Rule for Sums:

The derivative of a sum is the sum of the derivatives.
If
  z = ( f(x) + g(x) )
then the derivative of z is
  z' = ( f(x) + g(x) )'
    = f '(x) + g'(x)

So our example,

z = ( ((p)*p)5 ) - ( 2*p2 ) - ( p )
we can think of as
z = f(p) - g(p) - h(p)
So the derivative is
z ' = ( f(p) - g(p) - h(p) )'
  = f '(p) - g '(p) - h '(p)  
  = ( ((p)*p)5) ' - ( 2*p2) ' - ( p) '  
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ((p)*p)5 )' = (p)*5*((p)*p)4 (by the chain rule)
( 2*p2 )' = 2*2*p (by the rule for constant multiples, and the power rule)
( p )' = 1 (by the derivative rule for variables)
so the finished derivative is
z ' = (p)*5*((p)*p)4 - 2*2*p - 1  
  = (5p)*((p)*p)4 - 4*p - 1
[]


additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
previous page
Page Generated: Sun Nov 23 06:35:29 2025
Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.