Derivatives of Sums

Example:
G = (2 + ln(2)) z8 + 2*z - 5

The first thing to notice when finding the derivative of this function is that it is the sum of several terms, as shown in color below:

G = ( (2 + ln(2)) z8 ) + ( 2*z ) - ( 5 )

The Derivative Rule for Sums:

The derivative of a sum is the sum of the derivatives.
If
  z = ( f(x) + g(x) )
then the derivative of z is
  z' = ( f(x) + g(x) )'
    = f '(x) + g'(x)

So our example,

G = ( (2 + ln(2)) z8 ) + ( 2*z ) - ( 5 )
we can think of as
G = f(z) + g(z) - h(z)
So the derivative is
G ' = ( f(z) + g(z) - h(z) )'
  = f '(z) + g '(z) - h '(z)  
  = ( (2 + ln(2)) z8) ' + ( 2*z) ' - ( 5) '  
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( (2 + ln(2)) z8 )' = (0 + 0) z8 + 8*(2 + ln(2)) z7 (by the product rule, and the derivative rule for sums, and power rule)
( 2*z )' = 2 (by the rule for constant multiples, and the derivative rule for variables)
( 5 )' = 0 (by the derivative rule for constants)
so the finished derivative is
G ' = (0 + 0) z8 + 8*(2 + ln(2)) z7 + 2 - 0  
  = 8*z7 (2 + ln(2)) + 2
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additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.