Derivatives of Sums
Example:
z = ((p)*p)5 - 2*p2 - p
The first thing to notice when finding the derivative of this function
is that it is
the sum of several terms,
as shown in color below:
| z |
= |
( ((p)*p)5 ) | - |
( 2*p2 ) |
- |
( p ) |
The Derivative Rule for Sums:
The derivative of a sum is the sum of the derivatives.
If
then the derivative of
z is
| |
z' |
= |
( f(x) |
+ |
g(x) )' |
| |
|
= |
f '(x) |
+ |
g'(x) |
So our example,
| z |
= |
( ((p)*p)5 ) | - |
( 2*p2 ) |
- |
( p ) |
we can think of as
So the derivative is
| z ' |
= ( |
f(p) |
- |
g(p) |
- |
h(p) |
)' |
| |
= |
f '(p) |
- |
g '(p) |
- |
h '(p) |
|
| |
= |
( ((p)*p)5) ' |
- |
( 2*p2) ' |
- |
( p) ' |
|
and we just need to know each of the derivatives on the right-hand
side of the equation. In this case these are
so the finished derivative is
| z ' |
= |
(p)*5*((p)*p)4 |
- |
2*2*p |
- |
1 |
|
| |
= |
(5p)*((p)*p)4 - 4*p - 1 |
additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose,
University of Michigan Math Dept.