Derivatives of Sums

Example:
r(t) = sqrt(3*t2 - 4) - t7 + ln(2)

The first thing to notice when finding the derivative of this function is that it is the sum of several terms, as shown in color below:

r(t) = ( sqrt(3*t2 - 4) ) - ( t7 ) + ( ln(2) )

The Derivative Rule for Sums:

The derivative of a sum is the sum of the derivatives.
If
  z = ( f(x) + g(x) )
then the derivative of z is
  z' = ( f(x) + g(x) )'
    = f '(x) + g'(x)

So our example,

r(t) = ( sqrt(3*t2 - 4) ) - ( t7 ) + ( ln(2) )
we can think of as
r(t) = f(t) - g(t) + h(t)
So the derivative is
r '(t) = ( f(t) - g(t) + h(t) )'
  = f '(t) - g '(t) + h '(t)  
  = ( sqrt(3*t2 - 4)) ' - ( t7) ' + ( ln(2)) '  
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( sqrt(3*t2 - 4) )' = (1/2)*(3*t2 - 4)-1/2 (3*2*t - 0) (by the chain rule)
( t7 )' = 7*t6 (by the power rule)
( ln(2) )' = 0 (by the derivative rule for constants)
so the finished derivative is
r '(t) = (1/2)*(3*t2 - 4)-1/2 (3*2*t - 0) - 7*t6 + 0  
  = 3*t (3*t2 - 4)-1/2 - 7*t6
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additional explanation for the derivative of sums
see another derivative of sums example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.