Derivatives of Products

Example:
y = sin(e*x + 8) (ln(x) + e)

The first thing to notice when finding the derivative of this function is that it is the product of several terms, as shown in color below:

y = ( sin(e*x + 8)) ( ln(x) + e)

The Derivative Rule for Products:

The derivative of a product is the derivative of the first term times the second (and third, etc.) term(s), plus the first (and third, etc.) term(s) times the derivative of the second, etc.
If
  z = (f(x) g(x))
then the derivative of z is
  z ' = (f(x) g(x))'
    = f '(x) g(x) + f(x) g '(x)

So our example,

y = ( sin(e*x + 8)) ( ln(x) + e)
we can think of as
y = f(x) g(x)    
So the derivative is
y ' = ( f(x) g(x) )'    
  = f '(x) g(x) + f(x) g '(x)
  = ( sin(e*x + 8) )' ( ln(x) + e ) + ( sin(e*x + 8) ) ( ln(x) + e )'
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( sin(e*x + 8) )' = cos(e*x + 8) (e + 0) (by the chain rule)
( ln(x) + e )' = x-1 + 0 (by the derivative rule for sums, derivative rules for basic functions, and the derivative rule for constants)
so the finished derivative is
y ' = ( cos(e*x + 8) (e + 0) ) ( ln(x) + e ) + ( sin(e*x + 8) ) ( x-1 + 0 )
  = e*cos(e*x + 8) (ln(x) + e) + x-1 sin(e*x + 8)
[]


additional explanation for the product rule
see another product rule example
practice gateway test
previous page
Page Generated: Sat Nov 22 10:55:22 2025
Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.