The first thing to notice when finding the derivative of this function is that it is a composition of two functions, as shown below:
| V | = | sqrt( |
| where | |
= | et + t-1/4 |
The Chain Rule (Derivative Rule for Compositions):
If
|
Or, if
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So our example,
| V | = | sqrt( |
| where | |
= | et + t-1/4 |
| V | = | f( |
, where | |
= | g(t) | = | et + t-1/4 |
| V ' | = ( | f( |
)' | |
| = | f '( |
( |
||
| = | ( sqrt( |
( et + t-1/4 )' | ||
| ( sqrt( |
= | (1/2)*( |
(by the power rule, with exponent 1/2) |
| ( et + t-1/4 )' | = | ( et + (-1/4)*t-5/4 ) | (by the derivative rule for sums, derivative rules for basic functions, and the power rule) |
| V ' | = | (1/2)*( |
( et + (-1/4)*t-5/4 ) |
| = | (1/2)*(et + t-1/4)-1/2 | ( et + (-1/4)*t-5/4 ) | |
| = | (1/2)*(et + t-1/4)-1/2 (et - (1/4)*t-5/4) | ||