Derivatives of Compositions

Example:
B(z) = (sqrt(z))-p

The first thing to notice when finding the derivative of this function is that it is a composition of two functions, as shown below:

B(z) = ([])-p
  where  [] = sqrt(z)

The Chain Rule (Derivative Rule for Compositions):

The derivative of a composition is the product of the derivative of the outer function (with the inner function plugged in) and the derivative of the inner function.
If
  z = f( g(x) )
then the derivative of z is
  z' = ( f(g(x)) )'
    = f '(g(x)) g '(x)
Or, if
  z = f( [] ), where [] = g(x)
then the derivative of z is
  z' = ( f( [] ) )'
    = f '( [] ) ( [] )'
    = f '( [] ) g '(x)

So our example,

B(z) = ([])-p
  where  [] = sqrt(z)
we can think of as
B(z) = f( [] ) , where  [] = g(z) = sqrt(z)
So the derivative is
B '(z) = ( f( [] ) )'
  = f '( [] ) ( [] )'  
  = ( ([])-p )' ( sqrt(z) )'
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ([])-p )' = (-p)*([])-p-1 (by the power rule)
( sqrt(z) )' = ( (1/2)*z-1/2 ) (by the power rule, with exponent 1/2)
so the finished derivative is
B '(z) = (-p)*([])-p-1 ( (1/2)*z-1/2 )
  = (-p)*(sqrt(z))-p-1 ( (1/2)*z-1/2 )
  = (1/2(-p))*z-1/2 (sqrt(z))-p-1
[]


additional explanation for the chain rule
see another chain rule example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.