Derivatives of Compositions

Example:
y = (10*t2 + p)p

The first thing to notice when finding the derivative of this function is that it is a composition of two functions, as shown below:

y = ([])p
  where  [] = 10*t2 + p

The Chain Rule (Derivative Rule for Compositions):

The derivative of a composition is the product of the derivative of the outer function (with the inner function plugged in) and the derivative of the inner function.
If
  z = f( g(x) )
then the derivative of z is
  z' = ( f(g(x)) )'
    = f '(g(x)) g '(x)
Or, if
  z = f( [] ), where [] = g(x)
then the derivative of z is
  z' = ( f( [] ) )'
    = f '( [] ) ( [] )'
    = f '( [] ) g '(x)

So our example,

y = ([])p
  where  [] = 10*t2 + p
we can think of as
y = f( [] ) , where  [] = g(t) = 10*t2 + p
So the derivative is
y ' = ( f( [] ) )'
  = f '( [] ) ( [] )'  
  = ( ([])p )' ( 10*t2 + p )'
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ([])p )' = (p)*([])p-1 (by the power rule)
( 10*t2 + p )' = ( 10*2*t + 0 ) (by the derivative rule for sums, rule for constant multiples, and the derivative rule for constants)
so the finished derivative is
y ' = (p)*([])p-1 ( 10*2*t + 0 )
  = (p)*(10*t2 + p)p-1 ( 10*2*t + 0 )
  = (20p)*t (10*t2 + p)p-1
[]


additional explanation for the chain rule
see another chain rule example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.