Derivatives of Compositions

Example:
V = (9*x + sin(9))-1/4

The first thing to notice when finding the derivative of this function is that it is a composition of two functions, as shown below:

V = ([])-1/4
  where  [] = 9*x + sin(9)

The Chain Rule (Derivative Rule for Compositions):

The derivative of a composition is the product of the derivative of the outer function (with the inner function plugged in) and the derivative of the inner function.
If
  z = f( g(x) )
then the derivative of z is
  z' = ( f(g(x)) )'
    = f '(g(x)) g '(x)
Or, if
  z = f( [] ), where [] = g(x)
then the derivative of z is
  z' = ( f( [] ) )'
    = f '( [] ) ( [] )'
    = f '( [] ) g '(x)

So our example,

V = ([])-1/4
  where  [] = 9*x + sin(9)
we can think of as
V = f( [] ) , where  [] = g(x) = 9*x + sin(9)
So the derivative is
V ' = ( f( [] ) )'
  = f '( [] ) ( [] )'  
  = ( ([])-1/4 )' ( 9*x + sin(9) )'
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ([])-1/4 )' = (-1/4)*([])-5/4 (by the power rule)
( 9*x + sin(9) )' = ( 9 + 0 ) (by the derivative rule for sums, rule for constant multiples, and the derivative rule for constants)
so the finished derivative is
V ' = (-1/4)*([])-5/4 ( 9 + 0 )
  = (-1/4)*(9*x + sin(9))-5/4 ( 9 + 0 )
  = (-9/4)*(9*x + sin(9))-5/4
[]


additional explanation for the chain rule
see another chain rule example
practice gateway test
previous page
Page Generated: Thu Jan 22 20:18:47 2026
Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.