Derivatives of Compositions

Example:
y = (sin(t))1/4

The first thing to notice when finding the derivative of this function is that it is a composition of two functions, as shown below:

y = ([])1/4
  where  [] = sin(t)

The Chain Rule (Derivative Rule for Compositions):

The derivative of a composition is the product of the derivative of the outer function (with the inner function plugged in) and the derivative of the inner function.
If
  z = f( g(x) )
then the derivative of z is
  z' = ( f(g(x)) )'
    = f '(g(x)) g '(x)
Or, if
  z = f( [] ), where [] = g(x)
then the derivative of z is
  z' = ( f( [] ) )'
    = f '( [] ) ( [] )'
    = f '( [] ) g '(x)

So our example,

y = ([])1/4
  where  [] = sin(t)
we can think of as
y = f( [] ) , where  [] = g(t) = sin(t)
So the derivative is
y ' = ( f( [] ) )'
  = f '( [] ) ( [] )'  
  = ( ([])1/4 )' ( sin(t) )'
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ([])1/4 )' = (1/4)*([])-3/4 (by the power rule)
( sin(t) )' = ( cos(t) ) (by the derivative rules for basic functions)
so the finished derivative is
y ' = (1/4)*([])-3/4 ( cos(t) )
  = (1/4)*(sin(t))-3/4 ( cos(t) )
  = (1/4)*(sin(t))-3/4 cos(t)
[]


additional explanation for the chain rule
see another chain rule example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.