To find an antiderivative of
f(
y), we go through
our list of integration methods:
- Recognize elementary antiderivatives
- Rewrite the integrand to make it easier
- Use substitution to reverse the chain rule or simplify the
integrand
- Use integration by parts
- Use inspection to see the value of a definite
integral
to find one that works for this integrand. In this case,
only one method is appropriate. We use substitution to rewrite the integrand in terms of
w = 5 +
e2y.
This is shown below.
Substitution:
Let
w = 5 +
e2y. Then
w' = 2
e2y, so
(1/2)
dw =
e2y dy.
The integral can therefore be rewritten as
e2y sqrt(5 +
e2y)
dy =

sqrt(
w) (1/2)
dw =
(1/3)
w3/2 +
C
Thus, substituting back for
w,
e2y sqrt(5 +
e2y)
dy =
(1/3) (5 +
e2y)
3/2 +
C
To evaluate the definite integral, we take this antiderivative,
evaluate it at the endpoints of the integral (-ln(2) and ln(2)),
and take the difference of the values. This gives
[ (1/3) (5 + e2(ln(2)))3/2 ] - [ (1/3) (5 + e2(-ln(2)))3/2 ] = 9 - 7sqrt(21)/8.