Derivatives of Quotients

Example:
y = sin(6*x - 8) / p*ix

The first thing to notice when finding the derivative of this function is that it is a quotient, as shown below:

y = sin(6*x - 8)
----------
p*ix

The Derivative Rule for Quotients:

The derivative of a quotient is the derivative of the numerator times the denominator minus the numerator times the derivative of the denominator, all divided by the denominator squared.
If
  z = ( f(x) )
----
g(x)
then the derivative of z is
  z ' = ( f(x) )'
----
g(x)
    = f '(x) g(x) - f(x) g '(x)  
----
( g(x) )2

So our example,

y = sin(6*x - 8)
----------
p*ix
we can think of as
y = f(x)
----------
g(x)
So the derivative is
y' = ( f(x) )'
----------
g(x)
  = f '(x) g(x) - f(x) g '(x)
----------
( g(x) )2
  = ( sin(6*x - 8) )' ( p*ix ) - ( sin(6*x - 8) ) ( p*ix )'
----------
( p*ix )2
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( sin(6*x - 8) )' = cos(6*x - 8) (6 - 0) (by the chain rule)
( p*ix )' = p*(ln(i))*ix (by the rule for constant multiples, and the derivative rules for basic functions)
so the finished derivative is
y' = ( cos(6*x - 8) (6 - 0) ) ( p*ix ) - ( sin(6*x - 8) ) ( p*(ln(i))*ix )
----------
( p*ix )2
  = (6p)*cos(6*x - 8) ix - (p(lni))*sin(6*x - 8) ix
----------
(p*ix)2
[]


additional explanation for the quotient rule
see another quotient rule example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.