Derivatives of Quotients

Example:
P = ln(q - 9) / (q3 + e)

The first thing to notice when finding the derivative of this function is that it is a quotient, as shown below:

P = ln(q - 9)
----------
q3 + e

The Derivative Rule for Quotients:

The derivative of a quotient is the derivative of the numerator times the denominator minus the numerator times the derivative of the denominator, all divided by the denominator squared.
If
  z = ( f(x) )
----
g(x)
then the derivative of z is
  z ' = ( f(x) )'
----
g(x)
    = f '(x) g(x) - f(x) g '(x)  
----
( g(x) )2

So our example,

P = ln(q - 9)
----------
q3 + e
we can think of as
P = f(q)
----------
g(q)
So the derivative is
P' = ( f(q) )'
----------
g(q)
  = f '(q) g(q) - f(q) g '(q)
----------
( g(q) )2
  = ( ln(q - 9) )' ( q3 + e ) - ( ln(q - 9) ) ( q3 + e )'
----------
( q3 + e )2
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( ln(q - 9) )' = (q - 9)-1 (1 - 0) (by the chain rule)
( q3 + e )' = 3*q2 + 0 (by the derivative rule for sums, power rule, and the derivative rule for constants)
so the finished derivative is
P' = ( (q - 9)-1 (1 - 0) ) ( q3 + e ) - ( ln(q - 9) ) ( 3*q2 + 0 )
----------
( q3 + e )2
  = (q - 9)-1 (q3 + e) - 3*q2 ln(q - 9)
----------
(q3 + e)2
[]


additional explanation for the quotient rule
see another quotient rule example
practice gateway test
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Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.