Derivatives of Quotients

Example:
R(x) = sqrt(4*x) / (ex + 1/2)

The first thing to notice when finding the derivative of this function is that it is a quotient, as shown below:

R(x) = sqrt(4*x)
----------
ex + 1/2

The Derivative Rule for Quotients:

The derivative of a quotient is the derivative of the numerator times the denominator minus the numerator times the derivative of the denominator, all divided by the denominator squared.
If
  z = ( f(x) )
----
g(x)
then the derivative of z is
  z ' = ( f(x) )'
----
g(x)
    = f '(x) g(x) - f(x) g '(x)  
----
( g(x) )2

So our example,

R(x) = sqrt(4*x)
----------
ex + 1/2
we can think of as
R(x) = f(x)
----------
g(x)
So the derivative is
R(x)' = ( f(x) )'
----------
g(x)
  = f '(x) g(x) - f(x) g '(x)
----------
( g(x) )2
  = ( sqrt(4*x) )' ( ex + 1/2 ) - ( sqrt(4*x) ) ( ex + 1/2 )'
----------
( ex + 1/2 )2
and we just need to know each of the derivatives on the right-hand side of the equation. In this case these are
( sqrt(4*x) )' = 4*(1/2)*(4*x)-1/2 (by the chain rule)
( ex + 1/2 )' = ex + 0 (by the derivative rule for sums, derivative rules for basic functions, and the derivative rule for constants)
so the finished derivative is
R(x)' = ( 4*(1/2)*(4*x)-1/2 ) ( ex + 1/2 ) - ( sqrt(4*x) ) ( ex + 0 )
----------
( ex + 1/2 )2
  = 2*(4*x)-1/2 (ex + 1/2) - sqrt(4*x) ex
----------
(ex + 1/2)2
[]


additional explanation for the quotient rule
see another quotient rule example
practice gateway test
previous page
Page Generated: Wed Jun 10 13:03:33 2026
Comments to Gavin LaRose
glarose@umich.edu
©2001 Gavin LaRose, University of Michigan Math Dept.